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Home/ Questions/Q 660769
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:11:35+00:00 2026-05-13T23:11:35+00:00

Let’s say I have an array of primitives or a list of objects, doesn’t

  • 0

Let’s say I have an array of primitives or a list of objects, doesn’t matter, is there a short way of doing this kind of check:

if (a_primitive == any_item_in_my_collection) {
    // do something
}

or

if (an_object_ref.equals(any_item_in_my_collection)) {
    // do something
}

without doing this

for (int i = 0; i < myArray.length; i++) {
    if (a_primitive == myArray[i]) {
        // do something
    }
}

Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:11:35+00:00Added an answer on May 13, 2026 at 11:11 pm

    Do you have to use arrays? Why not switch to Collection-based API?

    Then you can use Collection.contains(Object o).

    Returns true if this collection contains the specified element. More formally, returns true if and only if this collection contains at least one element e such that (o==null ? e==null : o.equals(e)).

    Depending on the implementation, this query can be answered in O(1) or O(log N).

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