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Home/ Questions/Q 9207825
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T00:28:23+00:00 2026-06-18T00:28:23+00:00

Lets say i have the following arrays in ruby contained in an array and

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Lets say i have the following arrays in ruby contained in an array and I don’t know how many arrays there will be or the length of them. An example below:

[["cat", "dog"],[1, 3, 5, 7],["morning", "afternoon", "evening"]]

what i want to do is have all combinations of results from picking 1 value from each array and returning it as an array of these combinations. Therefore, in the following example, there should be 2*4*3, or 24 possible unique results.

the result would be like :

result = [["cat", 1, "morning"], ["cat", 1, "afternoon"], ["dog", 5, "evening"] ...]

How would i go about doing this in ruby for a list of N arrays? I tried messing around with products and maps and injects but I cant get it working.

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  1. Editorial Team
    Editorial Team
    2026-06-18T00:28:24+00:00Added an answer on June 18, 2026 at 12:28 am

    EDIT Since you made it clear that you’re dealing with not just three arrays a1, a2 and a3 but an arrays of arrays, changing my solution to use product.

    Like this?

     a1.map{|x1| a2.map{|x2| a3.map{|x3| [x1, x2, x3] }}}.flatten(2)
    

    Or with flat_map:

     a1.flat_map{|x1| a2.flat_map{|x2| a3.map{|x3| [x1, x2, x3] }}}
    

    Wow, or just:

     a1.product(a2,a3)
    

    If you have several arrays (not just the fixed number of 3 in you first example),
    then:

     input = [["cat", "dog"],[1, 3, 5, 7],["morning", "afternoon", "evening"]]
     h,*rest = input
     result = h.product(*rest)
    
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