Question

Let’s say there is the following function:

void SetTheSize(const SIZE *size) { ... }

Is there any way to call that function without specifying the SIZE variable? e.g.,

SetTheSize((const SIZE*)&{10, 10});

edit:
I should had mentioned that the SIZE is a struct, without SIZE(int, int) constructor.

Answer 1

No, only thing nearest in C++ is to do like this:

void SetTheSize(const SIZE& size); //Change the pointer to const reference

And call it using an unnamed temporary variable: SetTheSize(SIZE(10,10));