Question

Like a good programmer I guess I’m trying to be lazy and make the program make anything but I’m starting to think this can’t be done this way so here it goes…

I have 27 variables a1,a2,a3,a4,a5,a6,a7,a8,a9,b1,b2,b3,etc,c1,c2,c3,etc…

I want the user to give me the numbers for each but I don’t want to do it manually I want to do it with a for something like this:

for(i=0;i<=0;i++)
{
char a= 'a'+i;
char b= 'b'+i;
char c= 'c'+i;

printf("give me 1st number in square\n");
scanf("%d",a);
printf("give me 2nd number in square\n");
scanf("%d",b);
printf("give me 3rd number in square\n");
scanf("%d",c);

}

Any idea how to make this? if there’s a way I would really appreciate you can tell me thank you very much XD

Yeah also if you can’t understand or want me to explain better tell me and I will try my best to remake this.

Answer 1

This is what arrays are for. Instead of having variables like a1, a2, a3, b1, b2, b3, etc., just have two arrays:

int a[5]; // a[0] through a[4]
int b[4]; // b[0] through b[3]

Then you can access the variables with expressions like a[i], where i is any integer (provided you don’t try to access outside the array bounds, of course).