Look at the code:
template <class x> struct Foo
{
int getX(x *p) { return(0); }
enum E12 { a };
};
template <> int Foo<int>::getX(int*)
{
return(-15);
}
template <> enum Foo<int>::E12
{
a, b, c
}
As it was discussed in Cannot overload function, the first specialization is legal and even works in MSVC. While the second specialization for enum does not even want to compile, saying “error C2988: unrecognizable template declaration/definition”.
It seems to me that C++ is making relaitively unlogical exception for methods. Enum is just an example. The same thing can be applied to member classes, typedefs, etc.
I will be happy is some body will comment on this.
This is a very obscure new feature of C++11. File a bug report with Microsoft, although it is unlikely it will be given priority as almost nobody is aware this is allowed. The correct syntax would be
I’ve filed a bug with GCC. Can someone test on recent Clang?
In C++03, only classes and functions may be explicitly specialized. From the standard, C++03 14.7.3/1:
A member enum is not such a case. (Generally speaking, an
enumtype is always defined only once at its first declaration.)To obtain a templated
enumortypedef, you can wrap it in a class template. In your case, it would be a member class template ofFoo. Such a construct is called a metafunction.C++11 also has alias templates, which are like templated typedefs, but they cannot be explicitly specialized.
The policy of only allowing classes and functions to be specialized, and then allowing such templates to encapsulate other things like
enumandtypedef, seems more consistent to me than allowing direct specialization ofenum. But, perhaps the language is going in your preferred direction.