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Home/ Questions/Q 1086391
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:48:26+00:00 2026-05-16T22:48:26+00:00

Look this code: $(‘#loader’).show(); $.post( ‘/action.php’, function( data ) { // do anything with

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Look this code:

$('#loader').show();
$.post( '/action.php', function( data ) {  
// do anything with data
$('#loader').hide(); 
}  );

The loader DIV has a GIF image simulating loading state, This code works well but the GIF stops when is waiting the data (post called) …

I want the gif moves ever independently of the other codes in execution.. I hope you understand my problem..

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:48:26+00:00Added an answer on May 16, 2026 at 10:48 pm

    I believe you want the behavior listed in the example on the jQuery documentation website.

    jQuery:ajaxStart

    You can hide the image with the ajaxStop event handler.

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