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Editorial Team
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Asked: 2026-06-18T09:18:24+00:00

ls | grep -P $1 | awk ‘{ x += $5 } END {

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ls | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }'

This code is returning 0 using “[0-9]” as reg expr, in current folder there are 2 files named: “1” and “6”, each one with size of 138bytes.

Anyone could help me to find the problem?

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1 Answer

  1. Editorial Team

    You’re just missing the -l option to ls.

    ls -l | grep -P "$1" | awk '{ x += $5 } END { print "total bytes:" x }'
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