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Home/ Questions/Q 3406758
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:40:02+00:00 2026-05-18T05:40:02+00:00

main() { char buff[10]; int a; for(int i=0; i<10;i++) { cin >> buff[i]; a=sizeof(buff[i]);

  • 0
main()
{
    char buff[10];

    int a;

    for(int i=0; i<10;i++)

    {

        cin >> buff[i];

        a=sizeof(buff[i]);

        if(a==10)

            cout << "full";

    }

    for(int i=0; i<10;i++)

        cout << buff[i]<<"\n";

}

why des the control never comes to cout << “full”; i am new to coding…when i do dry run it works fine

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:40:03+00:00Added an answer on May 18, 2026 at 5:40 am

    Because in this code:

    a=sizeof(buff[i]);
    

    you are getting the size of one of the elements in the buff array — not of the whole array itself.

    And since the elements in the array are chars, the size will always be one (as dictated by the Standard).

    If you are trying to get the index of the element (that is, you want to hit on the 10th element), you need to do this:

     if(i==9)
            cout << "full";
    

    (9 instead of 10 because arrays are zero-based, and the 10th item is at buff[9]. First is buff[0], second at buff[1], etc…)

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