Question

My array contain date $a1[0] day $a1[1] month $a1[2] year I want the result as year/day/month give me one solution.

Below is my code

<?php
  $a1 = array("01","10","2012");
  $result = implode("/",$a1);
  print $result;
?>

This will print 01/10/2012 but I want this result 2012/01/10. How can I take the array manualy using implode function?

How can I take year first day second and month third?

Answer 1

You can’t use implode alone for that matter, if you are having exactly this pattern (elements order are inverted) the use this code (YYYY/MM/DD):

$a1 = array("01", "10", "2012");
$result = implode("/", array_reverse($a1));
print $result;

Else use a regex (YYYY/MM/DD):

$a1 = array("01", "10", "2012");
$result = preg_replace('/(\d{2})\/(\d{2})\/(\d{4})/', '$3/$2/$1', implode("/", $a1));
print $result;

If you need the format of (YYYY/DD/MM) then use this one:

$a1 = array("01", "10", "2012");
$result = preg_replace('/(\d{2})\/(\d{2})\/(\d{4})/', '$3/$1/$2', implode("/", $a1));
print $result;