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Home/ Questions/Q 3933970
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T23:39:43+00:00 2026-05-19T23:39:43+00:00

My code looks like this : try { String htmlPageText=readFromHtml(http://www.yahoo.com); } catch (Exception e)

  • 0

My code looks like this :

try
{
   String htmlPageText=readFromHtml("http://www.yahoo.com");
}
catch (Exception e)
{
  System.out.println("===Here===");
}

Method readFromHtml() will take a URL and return an HTML page. Normally it works fine. But I’m trying to simulate a “site down” situation, so I unplugged the Internet connection. I thought, the error should be caught and the result will be “===Here===”, but instead, it returned:

java.net.UnknownHostException: http://www.yahoo.com"

and never printed out “===Here===”. UnknownHostException is an extension of java.lang.Exception, so why was it not caught in the catch clause? Do I need a catch (UnknownHostException ex) to get it?

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  1. Editorial Team
    Editorial Team
    2026-05-19T23:39:43+00:00Added an answer on May 19, 2026 at 11:39 pm

    What is the readFromHTML method source code ? My guess is that this method throws some kind of exception but not UnknownHostException… Somewhere else in your code the exception is left unhandled.

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