Question

my first.h:

class skaiciavimas
{
public:
    vector<int> vekto[2];
    skaiciavimas();
    ~skaiciavimas();
....

my first.cpp

    #include "skaiciavimas.h"

skaiciavimas::skaiciavimas()
{   int i;
    for(i=0;i<2;i++)
    vekto[i].resize(3);
}
void skaiciavimas::showst(vector<int> st,int i)
{   
    vekto[i].at(0)=st.at(0);
    vekto[i].at(1)=st.at(1);
    vekto[i].at(2)=st.at(2);
    cout<<vekto[1].at(0)<<vekto[0].at(0)<<endl;

}
void skaiciavimas::tikrinimas ()
{
    cout<<vekto[1].at(0)<<vekto[0].at(0)<<endl;// gives always 0,0
....

there is second class from where i call shwst function
second.cpp:

vandenynas::vandenynas()
{
    vektorV.resize(3);
}
void vandenynas::duomenys (int i, int a, int a0) 
{
        switch (i)
    {
        case 0:
            vektorV.at(0)=a-a0;
            break;
        case 1:
            vektorV.at(1)=a-a0;
            break;
        default:
            vektorV.at(2)=a-a0;
            break;

    }
 sk.showst(vektorV,0);
}

the tikrinimas function i call from my main:

sk.tikrinimas();

why this line

cout<<vekto[1].at(0)<<vekto[0].at(0)<<endl;

alvays gives me 00, how to correct that to get the rigt numbers wich were assign in showst

P.S sk is my class (first sk;)

there is called duomenys and tikrinimas :

vandenynas vand;
skaiciavimas sk;
int main() 
{
    int i,a,a0,t;
    int j=1;

    while (j<3)
    {
        for (i=0;i<3;i++)
        {   
          cout<<"enter "<<kas<<kint(i)<<" kordinates"<<endl;
          cout<<kint(i)<<"0 = ";
          cin>>a0;
          cout<<kint(i)<<" = ";
          cin>>a;
          cout<<endl;
          if (j==1)
              vand.duomenys(i,a,a0);            
         }
     j++;
    }
    sk.tikrinimas();
...

Answer 1

      cin>>a0;

You read the input into local variables, but never call sk.showst with those values. It shouldn’t be surprising that it’s members are still whatever the defaults are.