Question

My last step involves getting the integer percent of the sum.
So if I enter:
2
1
1
2
The output should be:
2, which is 33.333% of the sum.
1, which is 16.666% of the sum.
1, which is 16.666% of the sum.
2, which is 33.333% of the sum.

Since I am very new to arrays, I am extremely puzzled. I don’t understand how to get the percent since user can enter any amount of integers. If it was only 2 integers, just say 2 and 2, they each would be 50 percent

import java.util.Scanner;
   public class Integers {
   /* program 7-1*/
      public static void main(String[] args) 
      {
         Scanner keyboard = new Scanner(System.in);
         System.out.println("How many numbers will you enter?");
         int size = keyboard.nextInt();
         int[] entry = new int[size];

         System.out.println("Enter " + entry.length + " integers, one per line:");

         int sum = 0;
         for (int index = 0; index < entry.length; index++)
         {
            entry[index] = keyboard.nextInt();
            sum +=  size;
         }

         System.out.println("The sum is " + sum + "." + "\nThe numbers are:" );         
      }
   }

Answer 1

Now that you have all entries and the sum, you are almost there:

• You need another loop to go over entries one at a time
• To calculate percentage, multiply the entry by 100.0, and then divide by the sum. Note the dot zero at the end of 100.0 – it’s there on purpose
• If you are on Java 5 or later, a very convenient way of printing out a number followed by percentage sign is printf. Note, however, that the percent sign % needs to be escaped.