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Home/ Questions/Q 8694383
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T00:46:29+00:00 2026-06-13T00:46:29+00:00

My question is: is there some most efficient solution for this code in ruby

  • 0

My question is:

is there some most efficient solution for this code in ruby on rails and mongoid odm?

messages_without_responses = Message.all.select{|message| message.sender == current_user || message.receiver == current_user}
messages = Array.new
messages_without_responses.each do |m|
  if m.message_responses.count > 0 
   messages << m
  else
   messages << m if m.receiver_id == current_user.id && m.place_receiver == "inbox"
  end
end

Thank you very much!

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  1. Editorial Team
    Editorial Team
    2026-06-13T00:46:30+00:00Added an answer on June 13, 2026 at 12:46 am

    I don’t know how many records are in your DB, but if the number might get large, you are better filtering out the records you want at the DB level rather than in Ruby. Hence the SQL conditions on Message.all (you’ll have to translate as necessary to make this usable with Mongoid; I’ve never used it before).

    ms = Message.all(:conditions => ["sender_id = ? OR receiver_id = ?", current_user.id, current_user.id])
    

    The rest is not bad, but you could make it more concise:

    ms.select { |m| m.message_responses.count > 0 || (m.receiver == current_user &&  m.place_receiver == "inbox")}
    
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