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Home/ Questions/Q 9174721
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T16:47:58+00:00 2026-06-17T16:47:58+00:00

My understanding of why arraylist is faster than a linkedlist is that with an

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My understanding of why arraylist is faster than a linkedlist is that with an arraylist you basically only need one action – update the reference at the end array element, whereas with a linked list you have to do much more e.g. create a new node, update 2 references, go through linked list and update the last node to point to the new one etc.

However I am not sure how java implement these. How does the arraylist know where the “last” element is, does it store a value of the last element or does it traverse the array and add a new element after the last?

And linked lists, do they store a reference to the last node in the list, or do they traverse the entire list to get to the end?

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  1. Editorial Team
    Editorial Team
    2026-06-17T16:47:59+00:00Added an answer on June 17, 2026 at 4:47 pm

    Look at the source:

    ArrayList:

    public boolean add(E e) {
        ensureCapacityInternal(size + 1);  // Increments modCount!!
        elementData[size++] = e;
        return true;
    }      
    

    LinkedList:

    public boolean add(E e) {
        linkLast(e);
        return true;
    }
    
    void linkLast(E e) {
        final Node<E> l = last;
        final Node<E> newNode = new Node<>(l, e, null);
        last = newNode;
        if (l == null)
            first = newNode;
        else
            l.next = newNode;
        size++;
        modCount++;
    }
    
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