Question

MyObject obj = new MyObject(para1);

In Java I can always do this while switching to C++ it gives me an error:conversion from ‘MyObject*’ to non-scalar type ‘MyObject’ requested.

It seems the way to fix it is MyObject* obj = new MyObject(para1);.

What if I want the object itself rather than the pointer to the object?

Would MyObject obj(para1);be the only way that works for me?

Since I’m switching from Java to C++, I also wonder:

MyObject* obj1 = new MyObject(para1);

If I print out the value of obj1, it would be an address.

MyObject obj2(para1);

What would be the printed-out value for obj2?

Answer 1

Would MyObject obj(para1);be the only way that works for me?

Yes, that is the normal way.

What would be the printed-out value for obj2?

If you haven’t overloaded the correct operator, you would get a compiler error. You define how your object is printed, using a function with the following signature:

std::ostream & operator<<(std::ostream & os, const MyObject & obj);