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Home/ Questions/Q 4612900
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T01:28:08+00:00 2026-05-22T01:28:08+00:00

new List<int>().GetType().Name is List`1. How do I get a name more like List<int> (

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new List<int>().GetType().Name is List`1. How do I get a name more like List<int> (not List<T>)?

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:28:09+00:00Added an answer on May 22, 2026 at 1:28 am

    One way would be using new List<int>().GetType().ToString(), which returns System.Collections.Generic.List`1[System.Int32].

    Or you could write yourself a small helper method along the lines of:

    string GetShortName(Type type)
    {
        string result = type.Name;
        if (type.IsGenericType)
        {
            // remove genric indication (e.g. `1)
            result = result.Substring(0, result.LastIndexOf('`'));
    
            result = string.Format(
                "{0}<{1}>",
                result,
                string.Join(", ",
                            type.GetGenericArguments().Select(t => GetShortName(t))));
        }
    
        return result;
    }
    

    which outputs strings like:

    List<Int32>
    List<T>
    Dictionary<List<Double>, Int32>
    Tuple<T1, T2, T3, T4>
    

    Note that for nested types, this would return only the innermost name.

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