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Home/ Questions/Q 7851253
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T19:07:29+00:00 2026-06-02T19:07:29+00:00

Normally, polar coordinates go from 0 to π to 2 π (just before 2

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Normally, polar coordinates go from 0 to π to 2π (just before 2π really, as it equals 0 again). However, when using the JavaScript atan2() function, I’m getting a different, weird range:

Cartesian X | Cartesian Y | Theta (θ)
===========================================================
     1      |      0      | 0 (0 × π)
     1      |      1      | 0.7853981633974483 (0.25 × π)
     0      |      1      | 1.5707963267948966 (0.5 × π)
    -1      |      1      | 2.356194490192345 (0.75 × π)
    -1      |      0      | 3.141592653589793 (1 × π)
    -1      |     -1      | -2.356194490192345 (-0.75 × π)
     0      |     -1      | -1.5707963267948966 (-0.5 × π)
     1      |     -1      | -0.7853981633974483 (-0.25 × π)

As you can see, after it reaches π (180°), it jumps down to –π (–180°), and proceeds back up to 0. How can I get it to use the range {0, …, 2π} instead of {–π, …, π}? I’ve been trying to think of every calculation to “fix” the values, but I would also like to know why JavaScript chooses this range instead of the typical polar range. Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-02T19:07:31+00:00Added an answer on June 2, 2026 at 7:07 pm

    It’s pretty standard for atan2 to return angles in that range; for instance, that’s what the atan2 in the C standard library does.

    If you want 0..2pi instead of -pi..pi, test whether the result is negative and add 2pi if it is.

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