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Home/ Questions/Q 8831779
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T08:23:12+00:00 2026-06-14T08:23:12+00:00

Not sure why im getting this error in my logs. PHP Notice: Undefined variable:

  • 0

Not sure why im getting this error in my logs.

PHP Notice: Undefined variable: customerName
here is line 74:
$arrOrderDetails = $purchaseOrder->load($customerName);

this im returning “$customerName” from the instance of another class
here is that code:

public function load($customerName){
$orderDetails = array();
//Adding first order detail
$orderData = array
    ('order_id' => 1, 
    'customer_name' => 'Lancaster Landscapes',
    'description' => 'Golf Balls-Titlest DT Solo', 
    'quantity' => 13,
    'price' => 33,
    'total' => 432.25
    );
$orderDetail = new OrderDetail($orderData);
$array_push($orderDetails, 1, $orderDetail);

return $orderDetails;

}

I will still be adding more elements to the array.
Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-06-14T08:23:14+00:00Added an answer on June 14, 2026 at 8:23 am

    Its just a notice, aka wont break the code, however if you want to clean it up , prior to $customername being assigned you include

     $customername='';
    

    That notice should go away

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