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Home/ Questions/Q 6103995
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:47:30+00:00 2026-05-23T13:47:30+00:00

NSUInteger index = [self.objects indexOfObject:obj]; if (index == NSNotFound) { // Success! Note: NSNotFound

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NSUInteger index = [self.objects indexOfObject:obj];

if (index == NSNotFound) {
    // Success! Note: NSNotFound internally uses NSIntegerMax
}

if (index == NSUIntegerMax) {
    // Fails!
}

Why? I’m suppose to get an unsigned value as a result of indexOfObject. So, naturally, i was assuming that if the object is not found, it will return NSUIntegerMax instead of NSIntegerMax. Is this a bug, or is there a logical explanation for this behavior.

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:47:31+00:00Added an answer on May 23, 2026 at 1:47 pm

    Perhaps NSNotFound can be used in contexts that use NSInteger. It is also safer, in case someone declares index as NSInteger instead of NSUInteger.

    At most, one could say that it’s odd that NSNotFound is defined as NSIntegerMax, but it’s certainly not a bug.

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