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Home/ Questions/Q 707111
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:14:27+00:00 2026-05-14T04:14:27+00:00

Ok so if I have this pattern: ab&bc&cd&de&ef And I need to replace all

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Ok so if I have this pattern:

ab&bc&cd&de&ef

And I need to replace all the ampersands except for the first one with commas so it ends up looking like this:

ab&bc,cd,de,ef

Its probably very simple but for the life of me I can’t get this one figured out…

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:14:27+00:00Added an answer on May 14, 2026 at 4:14 am

    It’s not that easy because JavaScript doesn’t do lookbehind.

    Try

    result = subject.replace(/(^(?:[^&]+&[^&]+)|[^&]+)&/g, "$1,");
    

    Explanation:

    ( Capture the following into backreference $1:

    ^(?:[^&]+&[^&]+) Start-of-string, followed by two fields separated by an ampersand

    | or

    [^&]+ one field (a field being one or more non-ampersand characters).

    ) End of capturing group

    & match an ampersand.

    That way, the first ampersand will be skipped in the match. If you need to handle empty fields, then use

    (^(?:[^&]*&[^&]*)|[^&]*)&
    
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