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Home/ Questions/Q 8774891
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T18:40:44+00:00 2026-06-13T18:40:44+00:00

Okay, here’s what I’m trying to program in C. I have an 8bit binary

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Okay, here’s what I’m trying to program in C.

I have an 8bit binary signal from an ADC on an ATmega32.

Now I want to convert that signal into an bar with 15LED’s that increases the higher the input value is.
So basically I want to cut my 8bit signal down to a 4bit one, convert it to decimal and show it at an increasing bar.

I first had the idea to check if my input is in a specific range (which would be always a range of 255/15) but I just couldn’t figure out how.

Just checking if the input is higher than a particular value won’t work because in that way there could be more than one condition at a time true.

Have you any idea how I could solve that? Any help is highly appreciated. 😉
Thank you!

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  1. Editorial Team
    Editorial Team
    2026-06-13T18:40:45+00:00Added an answer on June 13, 2026 at 6:40 pm

    Use this:

    uint8_t adc = GET_ADC_VALUE();
    
    // Say LED is a 16-bit register
    
    LED = (adc ? (1U << ((adc >> 4) + 1)) - 1 : 0x000);
    

    So only ADC value 0 has all LEDs off, all other ADC values power on 1 to 16 LEDs. This has the advantage of not using any division (ATmega has no divisor instruction).

    EDIT: The above code actually assumes 16 LEDs, if you have 15 LEDs just do:

    LED= (1U << (adc >> 4)) - 1;
    
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