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Home/ Questions/Q 5983189
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:11:42+00:00 2026-05-22T22:11:42+00:00

Okay, this one is beyond me: I must be having a long day. Why

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Okay, this one is beyond me: I must be having a long day. Why does (13! mod 10) come out as 4, when the number ends in two 0s??

Try this out:

<?php $thirteen_fac = 6227020800;
echo $thirteen_fac % 10; ?>

Result is 4. Expected 0.

I must be forgetting something exceedingly obvious…

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:11:42+00:00Added an answer on May 22, 2026 at 10:11 pm

    6227020800 is too large for an integer (on a 32 bit system anyway). PHP will store it as float in your variable. The modulo operation will thus use an inexact up/downrounded number as basis.

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