Question

One can easily define a function that accepts a 1d array argument like this:

int MyFunction( const float arr[] )
{    
    // do something here, then return...

    return 1

}

Although a definition such as:
int MyFunction( const float* arr ) would work as well.

How can one define a function that accepts a 2d array argument?

I know that this works:
int MyFunction( const float** arr ) — but, is it possible to use the first variation that uses []?

Answer 1

In C99, you can provide the dimensions of the array before passing it:

 void array_function(int m, int n, float a[m][n])
 {
      for (int i = 0; i < m; i++)
          for (int j = 0; j < n; j++)
              a[i][j] = 0.0;
 }


 void another_function(void)
 {
     float a1[10][20];
     float a2[15][15];
     array_function(10, 20, a1);
     array_function(15, 15, a2);
 }