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Editorial Team
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Asked: 2026-05-20T10:50:18+00:00

<?php $sql1= mysql_query(SELCT * FROM adds ORDER BY adds_id DESC ); while($row=mysql_fetch_array($sql1)){?> <tr> <td

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<?php
$sql1= mysql_query("SELCT * FROM adds ORDER BY adds_id DESC ");
while($row=mysql_fetch_array($sql1)){?> 
    <tr>
        <td width="134" valign="top" style="padding-left:10px;">
              <?php echo $row['image_name'];?>
        </td>

when I use this code I able to display a single image, but I want to display an image with refresh, means when user refresh – a new image will display.

Can this will be happen with rand() or need to any JavaScript

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1 Answer

  1. Editorial Team

    TRY

    <?php
$sql1= mysql_query("SELCT * FROM adds ORDER BY RAND() LIMIT 1");
while($row=mysql_fetch_array($sql1)){?> 
    <tr>
        <td width="134" valign="top" style="padding-left:10px;">
        <?php if(!empty($row['image_name']))  { ?>
           <img src="images/thumbs/thumb_<?php echo $row['image_name'];?>" />
        <?php } else { 
           echo "text wahatever";
         ?>
        </td>
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