Question

Please tell me why the output is as below for the following program. I am not getting the virtual classes in c++. observe the below code:

class B
{
public:
    B(char c = 'a') : m_c(c) {}

public:
    char get_c() const { return m_c; }
    void set_c(char c) { m_c = c; }

private:
    char m_c;
};

class C: public B
{ };

class D: public B
{ };

class E
    : public C
    , public D
{ };

int main()
{
    E e;
    C &c = e;
    D &d = e;
    std::cout << c.get_c();
    d.set_c('b');
    std::cout << c.get_c() << std::endl;
    return 0;
}

O/P: aa
I expect output would be ab. What would be the reason for getting “aa”??

If i have c.set_c(‘b’) instead of d.set_c(‘b’) then I will get O/P : “ab”, Here also, I am not getting why is it as such. Both c, d are referring to one object only.

class C:virtual public B{};
class D:virtual public B{};

If the class C, class D are inherited virtually from B, then
O/P would always be “ab”

Answer 1

consider class C : public B and C* c = new C then c point to an storage that begin with a B since C* is also B*. and this is true for class D : public B.

Now for class E : public C, public D and E* e = new E(). memory of e is something like:

{| B of C | other members of C }{| B of D | other members of D}

as you can see in above case we have 2 instance of B one for C and another for D and now it is obvious when you call ((D*)e)->set_c( 'b' ) you only change B instance of D and B instance of C will remain unchanged.

now when you say class C : public virtual B, C++ share B instance with any other class that virtually inherit from B. so in this case e is something like:

           | shared B |
    | C members | | D members |

and as you can see we have only one B so calling ((C*)e)->set_c and ((D*)e)->set_c will both act on same B.