Question

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Combining jQuery :not and :nth-child selectors

is this possible?

Here is my code:

$("ul#filterlist li:nth-child(3n)").css("marginTop", "0");

If I wanted to apply that to the list, but only to those items VISIBLE in the list (some get hidden, I don’t want them counted), how would it be achieved? I was thinking something like:

$("ul#filterlist li:nth-child(3n)").not(":hidden").css("marginTop", "0");

But it won’t work. Neither will anything I try with :visible

Any ideas? Thanks.

Answer 1

The method you’re looking for is filter(). It will filter down a list of jQuery objects based on the given selector. Since there was no “not :hidden” selector I could found, I used the opposite :visible.

$("ul#filterlist li:nth-child(3n)").filter(":visible").css("marginTop", "0");

Hope this helps!