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Home/ Questions/Q 6713813
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:25:26+00:00 2026-05-26T08:25:26+00:00

Possible Duplicate: Floating point inaccuracy examples Floating point comparison Computers are meant to be

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Possible Duplicate:
Floating point inaccuracy examples
Floating point comparison

Computers are meant to be good at arithmetic, aren’t they? Why does this print “False”?

double d1 = 1.000001;
double d2 = 0.000001;
Console.WriteLine((d1-d2)==1.0); 

or there result will be different in c sharp or java

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:25:27+00:00Added an answer on May 26, 2026 at 8:25 am

    I think result may vary depending on which processor and which language you’re using.
    This because float numbers (in general) are stored with a number of bits that try to represent that fractional number, but there can be some (very little) difference.
    So when you do (d1-d2) you probably get a number really close to 1.0, but not exactly 1.0!!

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