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Home/ Questions/Q 8498727
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T00:28:53+00:00 2026-06-11T00:28:53+00:00

Possible Duplicate: How to timeout a thread I am using a function call to

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Possible Duplicate:
How to timeout a thread

I am using a function call to make a recursive search in a tree. It sets the best answer in a class variable and the function itself doesn’t return anything.

So I want to limit the allowed time for the function. If the time has run out it simply stops and the thread is destroyed. How should I do if I want to limit the call to two seconds:

runFunction(search(),2000);
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  1. Editorial Team
    Editorial Team
    2026-06-11T00:28:55+00:00Added an answer on June 11, 2026 at 12:28 am

    Assuming you are using Java 5 or greater, I would use the ExecutorService interface and the submit method:

    ExecutorService executor = Executors.newSingleThreadExecutor();
    Future<?> future = executor.submit(new Runnable() {
    
    @Override
    public void run() {
        search();
        }
    });
    try {
        future.get(2000, TimeUnit.SECONDS);
    } catch (TimeoutException e) {
        // handle time expired
    }
    

    Using this method, you can also adjust your thread to return a value by submitting a Callable instead of a Runnable.

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