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Home/ Questions/Q 9155373
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:34:57+00:00 2026-06-17T12:34:57+00:00

Possible Duplicate: PHP: Notice: Undefined variable and Notice: Undefined index I need a really

  • 0

Possible Duplicate:
PHP: “Notice: Undefined variable” and “Notice: Undefined index”

I need a really help since I could not find the problem in my coding. I have an included pagination.php file in cutomer.php file. The follwoing “Notice: Undefined variable: page in F:\wamp\www…” notice is continuously popping up in every single page where I have included. Please help me. Thank you!

<?php

$query = "SELECT COUNT(*) as num FROM $tableName";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages['num'];

$stages = 3;

if(isset($_GET['page']))

$page = mysql_real_escape_string($_GET['page']);


if($page){                                 **//line 57**
    $start = ($page - 1) * $limit; 
}else{
    $start = 0; 
    }   

// Get page data
$query1 = "SELECT * FROM $tableName LIMIT $start, $limit";
$result = mysql_query($query1);

// Initial page num setup
if ($page == 0){$page = 1;}                **//line 68**
$prev = $page - 1;  
$next = $page + 1;  

Notice: Undefined variable: page in F:\wamp\www\homepage\includes\pagination.php on line 57
Notice: Undefined variable: page in F:\wamp\www\homepage\includes\pagination.php on line 68

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:34:57+00:00Added an answer on June 17, 2026 at 12:34 pm

    Just initialize $page before the if isset statement and the error should go away

    It is because if the if statement returns false, $page would be an undefined variable. The notice means that that the variable should be defined no matter what path the code takes.

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