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Home/ Questions/Q 8704119
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:01:13+00:00 2026-06-13T03:01:13+00:00

Possible Duplicate: PHP: Notice: Undefined variable and Notice: Undefined index I want when I

  • 0

Possible Duplicate:
PHP: “Notice: Undefined variable” and “Notice: Undefined index”

I want when I choose some value in a Select box to display a string for a number of times for example if I choosed the value 2 it will display a string twice.

this is the code I tried :

<!DOCTYPE HTML>
<html>
<head>
<script>
function checkIt()
{
    var getNum = document.getElementById("numb").value;

    //this_file.php ... im specifying for just. you specify this full code in any of file and specify the whole url path
    location.href="this_file.php?countIt="+getNum;
}
</script>
    <style type="text/css">
    .centrer
    {
        position: absolute;
        left: 50%;
        top: 50%;
        font-size:24px;
    }
    </style>

</head>
<body>
    <select name="nombres" id="numb" onchange="checkIt();">
        <option>1</option>
        <option>2</option>
        <option>3</option>
    </select>

<?php
if($_REQUEST["countIt"])
{
    $displayTimes = $_REQUEST["countIt"]; 
}
?>
   <div class="centrer">
    <?php
        $s = "Hello World! <br/>";
        for($i=0; $i<$displayTimes; $i++)
            echo $s;
    ?>
    </div>
</body>
</html>

but I have a problem :

Notice: Undefined variable: displayTimes in C:\Program
Files\EasyPHP-12.1\www\site\Untitled-1.php on line 43

notice that the line 43 is : for($i=0; $i<$displayTimes; $i++)

and also another problem that when I select the “1” Value it does anything, and also when I select other value the selected value in the select box still the value “1” and I have another question isn’t there any other way to do this without using JS only by using PHP ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:01:14+00:00Added an answer on June 13, 2026 at 3:01 am

    $displayTimes would only be declared if the condition was met, it was caused by the following :

    if($_REQUEST["countIt"]) <------------------- Condition 
    {
        $displayTimes = $_REQUEST["countIt"];
    }
    

    Replace the above with :

    $displayTimes = isset($_REQUEST["countIt"]) ? $_REQUEST["countIt"] : 0;
    
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