Question

Possible Duplicate:
Random permutation of integers using a random number generator

For example I need to make a random number from 1 to 30. But it doesn’t produce the same random number. The number produced has to be different one to another.

Is that possible?

Thanks

Answer 1

Create a List<Integer> containing 1-30, shuffle it using Collections.shuffle(), then iterate through the list. Of course, at the end of the list, it’s impossible to have a new number that hasn’t been generated yet.