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Home/ Questions/Q 6699379
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:41:18+00:00 2026-05-26T06:41:18+00:00

Possible Duplicate: Returning multiple values from a C++ function /************************************************/ /* Name: premserv */

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Possible Duplicate:
Returning multiple values from a C++ function

/************************************************/
/* Name: premserv                               */
/* Description: Calculations for premium serv   */
/* Parameters: N/A                              */
/* Return Value: premserv                       */
/************************************************/

float premserv ()
{
  int daymin = 0;         //Var for day minutes
  int nightmin = 0;       //Var for night minutes
  float daytotal = 0;     //Var for day total
  float nighttotal = 0;   //Var for night total
  float premserv = 0;     //Var for premium service cost

  cout << "\n" << "Please enter the number of minutes used durring the day (6AM - 6PM): " << "\n";
  cin >> daymin;
  cout << "\n" << "Please enter the number of minutes used durring the night (6PM - 6AM): " << "\n";
  cin >> nightmin;

  daytotal = (daymin - 75) * 0.1;
  nighttotal = (nightmin - 100) * 0.05;
  premserv = 25 + daytotal + nighttotal;

  return premserv;

}

I need to get the values from daymin, nightmin, and premserv out of the function. I only know how to get 1 value out of a function.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T06:41:19+00:00Added an answer on May 26, 2026 at 6:41 am

    You could use references.

    float premserv (int& daymin, int& nightmin)
    {
         float daytotal = 0;     //Var for day total
         float nighttotal = 0;   //Var for night total
         float premserv = 0;     //Var for premium service cost
    
         cout << "\n" << "Please enter the number of minutes used durring the day (6AM - 6PM): " << "\n";
         cin >> daymin;
         cout << "\n" << "Please enter the number of minutes used durring the night (6PM - 6AM): " << "\n";
         cin >> nightmin;
    
         daytotal = (daymin - 75) * 0.1;
         nighttotal = (nightmin - 100) * 0.05;
         premserv = 25 + daytotal + nighttotal;
    
         return premserv;
    }
    

    This will directly modify the values of daymin and nightmin and you could still keep premserv as a returned value (since it fits with the function name, I guess).

    You’d use it like so:

    int daymin = 0;
    int nightmin = 0;
    float premiumservice = premserv(daymin, nightmin);
    
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