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Size of character ('a') in C/C++

I am a beginner at C, and was confused by this.

C: I tried printing the sizeof( ‘a’ ) in C using the “%zu” modifier, and it prints a value 4.

C++: Printing sizeof( ‘a’ ) in C++ using cout, and printf(using the format above) both printed a value 1.

I believe the correct value should be 1, since ‘a’ will be taken as a char. Why doesn’t it return 4 in C? Are the sizeof operations of both different in both the languages? If so, what’s the difference, and why does it return a different value?
I used the gcc compilers in both cases.

Answer 1

In C, the 'a' is a character constant, which is treated as an integer, so you get a size of 4, whereas in C++ it’s treated as a char. This is a duplicate of the question here:

Size of character ('a') in C/C++