Question

Possible Duplicate:
Size of character ('a') in C/C++

OS: linuxmint 32-bit

Compiler: gcc & g++

I have try this code:

#include <stdio.h>

int main()
{
    printf("%d\n",sizeof('a'));
    return 0;
}

and I compile it with gcc , the result is 4, and I change to g++, and it is 1

then I use:
sizeof(char), and the result is 1

I use:
char s = ‘a’;
printf(‘%d\n’, sizeof(s));

and the result is 1

but I search in the Internet, and some people said that they get the result of 1 or 2.

So why there are so many different result?

Answer 1

Character constants are represented as int in C. When you are specifying char type, it’s only 1 byte.