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Home/ Questions/Q 597601
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:17:54+00:00 2026-05-13T16:17:54+00:00

Possible Duplicates: Ruby/Ruby on Rails ampersand colon shortcut What does map(&:name) mean in Ruby?

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Possible Duplicates:
Ruby/Ruby on Rails ampersand colon shortcut
What does map(&:name) mean in Ruby?

I was reading Stackoverflow and stumbled upon the following code

array.map(&:to_i)

Ok, it’s easy to see what this code does but I’d like to know more about &: construct which I have never seen before.

Unfortunately all I can think of is “lambda” which it is not. Google tells me that lambda syntax in Ruby is ->->(x,y){ x * y }

So anyone knows what that mysterious &: is and what it can do except calling a single method?

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:17:55+00:00Added an answer on May 13, 2026 at 4:17 pm

    There’s a few moving pieces here, but the name for what’s going on is the Symbol#to_proc conversion. This is part of Ruby 1.9 and up, and is also available if you use later-ish versions of Rails.

    First, in Ruby, :foo means “the symbol foo“, so it’s actually two separate operators you’re looking at, not one big &: operator.

    When you say foo.map(&bar), you’re telling Ruby, “send a message to the foo object to invoke the map method, with a block I already defined called bar“. If bar is not already a Proc object, Ruby will try to make it one.

    Here, we don’t actually pass a block, but instead a symbol called bar. Because we have an implicit to_proc conversion available on Symbol, Ruby sees that and uses it. It turns out that this conversion looks like this:

    def to_proc
      proc { |obj, *args| obj.send(self, *args) }
    end
    

    This makes a proc which invokes the method with the same name as the symbol. Putting it all together, using your original example:

    array.map(&:to_i)
    

    This invokes .map on array, and for each element in the array, returns the result of calling to_i on that element.

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