Question

Possible Duplicates:
string literal in c
Assigning strings to arrays of characters

I got the following code:

char result[3][4];

result[0] = "horse";
result[1] = "pig";
result[2] = "chicken";

It won’t compile saying Incompatible types in assignment. What am I doing wrong?

Answer 1

char is a single char, eg ‘h’

What you want is string pointers.

 char *result[3];

Remember if you do it this way you won’t be able to change the contents of an individual string (it is a constant and stored in a different place.)

You could also do something like this

 char *result[3];

 result[0] =  malloc(100 * sizeof(char));
 strcpy(result[0],"horse"); // or strncpy(result[0],5,"horse")
 etc