private List<T> newList;
public List<T> NewList
{
get{return newList;}
set{newList = value;}
}
I want to create something like this, but this is won’t work. it’s just an example to demonstrate my goal as it’s pretty common creating proprties for string and int and even T but I’ve never seen a List property
Is it even possible do such a thing, creating a property for type List ?
EDIT
I have a normal class that has normal properties (string properties, int properties, etc) but I have this property that stores user options, So on the presentation layer I had to convert them into a string so I could be able to store them in the Object. Now is it possible to have a property of type List to store the multivalues in a better and clean way, instead of converting information into one string and then split it and again join it! Thanks Again =D
EDIT2
private List<KeyValuePair<string, string>> _settings;
public List<KeyValuePair<string, string>> MySettings
{
get { return _settings; }
set { _settings = value; }
}
I used the exact code you posted but the property still won’t appear in the object’s instance, so I tried adding code in the get and set (I wonder why you left them empty or does it means something?) and also added a private variable in the class but still it doesn’t appear in the properties of the object’s instance!
I hope you could provide the exact code to implement this property and a simple code that assigns or retrieves from/to an instance of this class object
It’s the first time to even hear about this KeyValuePair and all the tutorials are pretty simple and not for my case, sorry!
The Last Edit: After a lot of researching and the help of Mark Avenius I found the perfect answer. hope everyone can benefit from this.
NOW! HOW TO CREATE A PROPERTY FOR A LIST :
The Options Class
Public Class Options
{
private string id;
private int option;
public int ID
{
get { return id; }
set { id= value; }
}
public string Option
{
get { return option; }
set { option = value; }
}
}
The Users Class
public class Users
{
private int userId;
private string pass;
private List<Options> userOptions = new List<Options>();
public int ID
{
get { return userId; }
set { user = userId; }
}
public string Pass
{
get { return pass; }
set { pass = value; }
}
public List<Options> OptionsList
{
get { return userOptions; }
set { userOptions = value; }
}
}
The Presentation Layer
Users newUser = new Users ();
Options userOption = new Options ();
userOption.ID = int.Parse(txtBxID.Text);
userOption.Option = txtBxOption.Text;
Item.Options.Add(userOption);
Tmust be defined within the scope in which you are working. Therefore, what you have posted will work if your class is generic onT:Otherwise, you have to use a defined type.
EDIT: Per @lKashef’s request, following is how to have a List property:
This can go within a non-generic class.
Edit 2:
In response to your second question (in your edit), I would not recommend using a list for this type of data handling (if I am understanding you correctly). I would put the user settings in their own class (or struct, if you wish) and have a property of this type on your original class:
This way, you have named properties that you can reference instead of an arbitrary index in a list. For example, you can reference
MySettings.FirstNameas opposed toMySettingsList[0].Let me know if you have any further questions.
EDIT 3:
For the question in the comments, your property would be like this:
EDIT 4: Based on the question’s edit 2, following is how I would use this:
You mentioned that “the property still won’t appear in the object’s instance,” and I am not sure what you mean. Does this property not appear in IntelliSense? Are you sure that you have created an instance of
MyClass(likemyClass.MySettingsabove), or are you trying to access it like a static property (likeMyClass.MySettings)?