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Editorial Team
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Asked: 2026-06-15T08:09:51+00:00

$ptn = /^Response.+?[:] /; $str = Response from Moore Auto: Thanks for your feedback;

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$ptn = "/^Response.+?[:] /";
$str = "Response from Moore Auto: Thanks for your feedback";
$rpltxt = "";
echo preg_replace($ptn, $rpltxt, $str);

“Moore Auto” is a variable name, so I simply need the text after the colon and space. Desired final result would be the string “Thanks for your feedback” in this case. Much appreciated!

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1 Answer

  1. Editorial Team

    Simple with substr() , like this:

    $str = 'Response from Moore Auto: Thanks for your feedback';
echo substr($str, strpos($str,':')+2);  //echoes "Thanks for your feedback"
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