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Home/ Questions/Q 6082249
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:16:06+00:00 2026-05-23T11:16:06+00:00

public class FinallyTest { static int i=0; public static void main(String a[]){ while(true){ try{

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  public class FinallyTest {
    static int i=0;
    public static void main(String a[]){
        while(true){
            try{
                i=i+1;
                return;
            }finally{
                i=i+1;
                break;
            }
        }
        System.out.println(i);
    }
}

In the above code output is ‘2’. What I was expecting was that nothing should be printed. What exactly does ‘break’ do here? Please explain. Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:16:06+00:00Added an answer on May 23, 2026 at 11:16 am

    The finally clause changes the “completion reason” for the try clause. For a detailed explanation, refer to JLS 14.20.2 – Execution of try-catch-finally, with reference to JLS 14.1 Normal and Abrupt Completion of Statements.

    This is one of those strange edge cases in the Java language. Best practice is not to deliberately change the control flow in a finally clause because the behavior is difficult for the reader to understand.

    Here’s another pathological example:

    // DON'T DO THIS AT HOME kids
    public int tricky() {
        try {
            return 1;
        } finally {
            return 2;
        }
    }
    
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