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Home/ Questions/Q 6334615
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:41:40+00:00 2026-05-24T18:41:40+00:00

public class Shapes { public virtual void Color() { Console.WriteLine(Shapes); } } public class

  • 0
public class Shapes
{
  public virtual void Color()
  {
    Console.WriteLine("Shapes");
  }
}

public class Square : Shapes
{
  public void Color()
  {
    Console.WriteLine("Square");
  }
}

public class Test
{ 
  public static void main()
  {
    Shapes s1 = new Shapes();
    s1.Color();
    Shapes s2 = new Square();
    s2.Color();
  }
}

I want to know if the base class has defined some methods virtual, then is it mandatory to override them in derive class? Similarly, If the base class method is abstract, we need to implement the method in derive class, but is override modifier is mandatory? What if override modifier is omitted.

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:41:41+00:00Added an answer on May 24, 2026 at 6:41 pm

    I want to know if the base class has defined some methods virtual,
    then is it mandatory to override them in derive class?

    Definitely not. It is up to the derived class to decide whether or not to override the virtual method. Note that some classes will recommend that derived classes override a particular virtual method in some cases, but the compiler will not enforce that.

    If the base class method is abstract, we need to implement the method
    in derive class, but is override modifier is mandatory?

    Yes, you need to use the override keyword, otherwise the method will be hidden by the definition in the derived class.

    If you actually run your code, you will see “Shapes” printed twice. That’s because the Color() method in the Squares class isn’t declared using the override keyword. As such, it hides the base class method. This means it will only be accessible through a variable of type Squares:

    Squares s3 = new Squares();
    s3.Color();
    

    This will print “Square”, since you’re calling the method on a variable of the correct type.

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