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Home/ Questions/Q 6553723
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:36:57+00:00 2026-05-25T12:36:57+00:00

public class TestingArray { public static void main(String[] args) { int iCheck = 10;

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public class TestingArray {

    public static void main(String[] args) {

        int iCheck = 10;
        int j = iCheck;
        j = 11;
        System.err.println("value of iCheck "+iCheck);

        int[] val1 = {1,2,9,4,5,6,7};
        int[] val2 = val1;
        val2[0] = 200;
        System.err.println("Array Value "+val1[0]);
    }
}

Output:

value of iCheck 10
Array Value 200

From the above code, I found that if any array val2 is being assigned to another array val1 and if we change any value of val2 array, the result is as well reflected for the array val1 while the same scenario is not with variable assignment.
Why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:36:58+00:00Added an answer on May 25, 2026 at 12:36 pm

    The following statement makes val2 refer to the same array as val1:

    int[] val2 = val1;
    

    If you want to make a copy, you could use val1.clone() or Arrays.copyOf():

    int[] val2 = Arrays.copyOf(val1, val1.length);
    

    Objects (including instances of collection classes, String, Integer etc) work in a similar manner, in that assigning one variable to another simply copies the reference, making both variables refer to the same object. If the object in question is mutable, then subsequent modifications made to its contents via one of the variables will also be visible through the other.

    Primitive types (int, double etc) behave differently: there are no references involved and assignment makes a copy of the value.

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