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Home/ Questions/Q 6576003
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:27:25+00:00 2026-05-25T15:27:25+00:00

public class TestSample { public static void main(String[] args) { System.out.print(Hi, ); System.out.print(args[0]); System.out.println(.

  • 0
public class TestSample {
    public static void main(String[] args) {
        System.out.print("Hi, ");
        System.out.print(args[0]);
        System.out.println(". How are you?");
    }
}

When I compile this program, I get this error:

Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 0


Also, why can’t I have an args which accepts an int array like this:

public static void main(int[] args) {
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:27:25+00:00Added an answer on May 25, 2026 at 3:27 pm

    1. ArrayIndexOutOfBoundsException: 0

    It was thrown because args.length == 0 therefore args[0] is outside the arrays range of valid indices (learn more about arrays).

    Add a check for args.length>0 to fix it.

    public class TestSample {
        public static void main(String[] args) {
            System.out.print("Hi, ");
            System.out.print(args.length>0 ? args[0] : " I don't know who you are");
            System.out.println(". How are you?");
       }
    }
    

    2. Command line args as int

    You will have to parse the arguments to int[] yourself as the command line arguments are passed only as a String[]. To do this, use Integer.parseInt() but you will need exception handling to make sure the parsing went OK (learn more about exceptions). Ashkan’s answer shows you how to do this.

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