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Home/ Questions/Q 4099500
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T20:26:31+00:00 2026-05-20T20:26:31+00:00

public static String getElementXpath(DOMElement elt){ String path = ; for (; elt != null;

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  public static String getElementXpath(DOMElement elt){
        String path = ""; 

        for (; elt != null; elt = (DOMElement) elt.getParentNode()){

            System.out.println("THIS ONE " + path);
        }
        System.out.println("NEXT ONE " + path);
        return path;                            
    }

NEXT ONE doesn’t even print. I’ve tried adding anything after the for loop but they don’t seem to be running. Shouldn’t there be exception that is raised that I can catch? My main method which executes the function getElementXpath throws Exception. I tried removing the throw Exception and same result.

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  1. Editorial Team
    Editorial Team
    2026-05-20T20:26:32+00:00Added an answer on May 20, 2026 at 8:26 pm

    Swallowing an exception somewhere else seems to be the only explanations possible. Encapsulate the loop in a try-catch block, print the exception and rethrow. For testing, catch Throwable. Maybe add a finally block, too.

    My main method which executes the function getElementXpath throws Exception.

    This doesn’t matter, there may be a RuntimeException or even an Error. You shouldn’t declare throws Exception without a reason, but it can’t be the culprit here.

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