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Home/ Questions/Q 988267
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:36:53+00:00 2026-05-16T05:36:53+00:00

public Subclass(String[] parameters) throws IllegalArgumentException { super(Rectangle, Double.parseDouble(parameters[0]), Double.parseDouble(parameters[1]), 90, Double.parseDouble(parameters[2]), Double.parseDouble(parameters[3])); if(parameters.length !=

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public Subclass(String[] parameters) throws IllegalArgumentException {
    super("Rectangle",
        Double.parseDouble(parameters[0]),
    Double.parseDouble(parameters[1]),
    90,
    Double.parseDouble(parameters[2]),
    Double.parseDouble(parameters[3]));
            if(parameters.length != 4) throw new IllegalArgumentException("bla, bla");
    if(parameters == null) throw new IllegalArgumentException("bla, bla");
}

I would like to put these 2 if statements before calling super-constructor. I know that I can’t do that, so what’s the painless way to do that kind of parsing of parameters (throwing Exception) before calling super()?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:36:54+00:00Added an answer on May 16, 2026 at 5:36 am

    Declare a validation method taking String[] and returning it:

    private static String[] validate(String[] param) {
        // do validation here
        return param;
    }
    

    And call it when using param first time

    super("Rectangle", Double.parseDouble(validate(param).parameters[0]),
    

    This trick solves problem quickly, but, as another poster noted, sometimes it’s better to refactor your API (like creating a factory method).

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