Question

public void m1(Integer f) {
    ...
}

public void m1(Float f) {
    ...
}

public void main() {
    m1(null); // error: the method m1(Integer) is ambiguous for the type Main
    m1((Integer) null); // success
}

Given the above example, we can admit in some ways that null is typed. So why do the following lines print true? Sure o1 and o2 both have no value (i.e. null), but they aren’t from the same type (Integer vs Float). I firstly thought false would have been printed.

Integer i = null;
Object o1 = (Object) i;
Float f = null;
Object o2 = (Object) f;
System.out.println(o1 == o2); // prints true

// in short:
System.out.println(((Object) ((Integer) null)) == ((Object) ((Float) null))); // prints true

Answer 1

All null values are untyped and are equal. You can pass it to different reference types but it makes no difference for comparison purposes.

It is not the null value which is typed but the reference to the null which can be typed.

A common question is what happens here

class A {
    public static void hello() { System.out.println("Hello World"); }

    public static void main(String... args) {
        A a = null;
        a.hello();
        System.out.println("a is an A is " + (a instanceof A)); // prints false.
    }
}

The compiler sees the type of a as an A so the static method is called. But the value referenced is null and untyped.

The only operations you can perform with null without causing a NullPointerException is to assign or pass it without examining it or comparing it with another reference.

BTW

In short: The compiler will select a method based on the type of the reference, at runtime the execution is based on the class of the object referenced. At runtime null is treated as any type or no type or you get a NullPointerException if you try to dereference it.