Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 129553
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T05:48:28+00:00 2026-05-11T05:48:28+00:00

Quickie: Table structure: id | name | parent_id I want to run a query

  • 0

Quickie:

Table structure:

id | name | parent_id 

I want to run a query for ID’s, but also return that item’s parent_id and the name of that id as well.

To better explain

SELECT id, name FROM sections 

…then for each ID, return the ID and name of its parent using the ‘parent_id’ column.

I’m trying to get this into an array:

[0]     [id]     [name]     [parent_id]     [parent_name] 
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T05:48:29+00:00Added an answer on May 11, 2026 at 5:48 am

    This should work:

    SELECT s.id, s.name, s.parent_id, p.name as parent_name FROM sections s LEFT JOIN sections p ON s.parent_id = p.id 

    Basically you just want to join the table against itself and bring in the name field as the parent name.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Quickie-Question: To summarize, I'm a little confused as to how I would design such
A quickie, and hopefully an easy one. I'm following the docs at http://docs.djangoproject.com/en/dev/topics/auth/ to
My experience with databases is with fairly small web applications, but now I'm working
This is my first time posting on Stackoverflow, but I've been reading through many
Quickie pseudo-aesthetics question: For field declarations, the following is allowed: int i, j, k;
Quickie question: I'm toying with some of the new taskbar APIs in Windows 7
I am writing a quickie BlackJack Winforms app to demonstrate a couple of concepts.
Just a quickie to get a feel for the community in general's preference: When
It should be a quickie to VBA/Excel experts. I have a large 60 to
Hopefully a quickie... I'd like to know how/where to alter the settings in argouml

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.