Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8776083
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T18:57:56+00:00 2026-06-13T18:57:56+00:00

$r1 = mysql_query( SELECT *, SUM(bps.price) as sum FROM accounts FULL JOIN bps on

  • 0
$r1 = mysql_query("
SELECT *, SUM(bps.price) as sum FROM accounts 
FULL JOIN bps on bps.id = mid
");
echo "Total price: ".$row['price']."<br>" ;
    while($row = mysql_fetch_array($r1))
      {
      echo $row['name']." <b>:::</b>  ".$row['mid']." <b>:::</b>  ".$row['price'];
      echo "<br />";
      }

this is my query. I need to get the total(the sum) of the column : bps.price
some of the rows have : 10.5 , others -5.5 etc… in other words some are negative values and others are positive.It will list all the results then at the end display the sum of column price.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T18:57:57+00:00Added an answer on June 13, 2026 at 6:57 pm

    Does this work the way you want? I’m not sure which columns belong to which tables, just edit the table names (a / b) as needed…

    $r1 = mysql_query("
    SELECT *, sum(a.price) as sum FROM accounts as a 
    FULL JOIN bps as b on a.mid = b.id
    ");
    echo "Total price: ".$row['sum']."<br>" ;
        while($row = mysql_fetch_array($r1))
          {
          echo $row['a.name']." <b>:::</b>  ".$row['a.mid']." <b>:::</b>  ".$row['a.price'];
          echo "<br />";
          }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

$result = mysql_query(SELECT * FROM project ORDER BY projectid); while($row = mysql_fetch_array($result)) { return(array($row['projectid'],
$result = mysql_query(SELECT SUM(TOTAL) AS total FORM price_db); $row = mysql_fetch_assoc($result); $sum = $row['total'];
$query = mysql_query(SELECT sum(rating) FROM stars WHERE post_id = 20); echo $query; It outputs:
MyCode $query = mysql_query(SELECT COUNT(`op_id`) FROM `room_group_options` WHERE `group` = '$group'); echo $query; $result
we've codeded this PHP-Script: function price($id) { $ergebnis = mysql_query(SELECT * FROM preiszuordnungen where
function get_total_adults() { $sql = SELECT SUM(number_adults_attending) as number_of_adults FROM is_nfo_rsvp; $result = mysql_query($sql)
GOT error for the following query in MYSQL(version5.1) SELECT year,month,sum(fact_1),sum(fact_2),sum(fact_3),sum(fact_4) from( select year,month,fact_1,fact_2,0 as
this is the mysql query SELECT * FROM users AS up JOIN users AS
$line = @mysql_query(SELECT * FROM clips, userclips WHERE userclips.userid='$id' AND userclips.clipid=clips.id ORDER BY clips.title);
I have this code, $sqlstr = mysql_query( SELECT * FROM sales where passport =

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.