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Home/ Questions/Q 549779
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:13:09+00:00 2026-05-13T11:13:09+00:00

Recently, a correspondent mentioned float.as_integer_ratio() , new in Python 2.6, noting that typical floating

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Recently, a correspondent mentioned float.as_integer_ratio(), new in Python 2.6, noting that typical floating point implementations are essentially rational approximations of real numbers. Intrigued, I had to try π:

>>> float.as_integer_ratio(math.pi);
(884279719003555L, 281474976710656L)

I was mildly surprised not to see the more accurate result due to Arima,:

(428224593349304L, 136308121570117L)

For example, this code:

#! /usr/bin/env python
from decimal import *
getcontext().prec = 36
print "python: ",Decimal(884279719003555) / Decimal(281474976710656)
print "Arima:  ",Decimal(428224593349304) / Decimal(136308121570117)
print "Wiki:    3.14159265358979323846264338327950288"

produces this output:

python:  3.14159265358979311599796346854418516
Arima:   3.14159265358979323846264338327569743
Wiki:    3.14159265358979323846264338327950288

Certainly, the result is correct given the precision afforded by 64-bit floating-point numbers, but it leads me to ask: How can I find out more about the implementation limitations of as_integer_ratio()? Thanks for any guidance.

Additional links: Stern-Brocot tree and Python source.

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:13:10+00:00Added an answer on May 13, 2026 at 11:13 am

    The algorithm used by as_integer_ratio only considers powers of 2 in the denominator. Here is a (probably) better algorithm.

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