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Home/ Questions/Q 7663955
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T14:10:47+00:00 2026-05-31T14:10:47+00:00

${requestScope[‘javax.servlet.forward.servlet_path’]} gets me the right string, but not including parameters that might be set

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${requestScope['javax.servlet.forward.servlet_path']} gets me the right string, but not including parameters that might be set in the url.

Example:

http://localhost/path/i/want?param=1 should give me a string /path/i/want?param=1

I have a feeling this should be done easily but can’t figure it out.

Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-31T14:10:49+00:00Added an answer on May 31, 2026 at 2:10 pm

    It’s available by ${requestScope['javax.servlet.forward.query_string']}.

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