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Home/ Questions/Q 7589195
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T20:06:08+00:00 2026-05-30T20:06:08+00:00

Right now, I am using the helper method raw to output content from a

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Right now, I am using the helper method raw to output content from a helper method

Here’s my view:

%ul.unstyled.barges.sortable.connectedSortable.ui-widget-content
  = raw show_list(list, columns)

And here’s my helper:

def show_list(list, columns)
  content = ""
    0.upto(columns) do |c|
      content << render(:partial => 'barges/barge', :locals => {:barge => list.select{|barge| barge.location_column == c}.first})
    end
  content
end

Is there a way to eliminate the necessity to use raw? If I don’t use raw, then the html will be returned as a string to the view.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T20:06:09+00:00Added an answer on May 30, 2026 at 8:06 pm

    If you’re sure the content is always going to be safe to output as HTML (i.e. no user input), you can return content as html_safe from your helper:

    def show_list(list, columns)
      content = ""
        0.upto(columns) do |c|
          content << render(:partial => 'barges/barge', :locals => {:barge => list.select{|barge| barge.location_column == c}.first})
        end
      content.html_safe
    end
    
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